Awk Extracting Only Printable Characters From A Column

Awk Extracting Only Printable Characters From A Column I would like to print column4 if column5 is empty desired output filename ARP I used the following code But this code prints only the filenames awk if FNR 1 print FILENAME if 5 printf 4 END printf n txt

2 Answers Sorted by 5 You could do it with a simple awk command to print the last column contents and using a multiple spaces as the field separator Since the default separator in awk is a single white space using it directly on the last column would split the contents of the last column Extract specific columns from delimited file using Awk Sorry if this is too basic I have a csv file where the columns have a header row v1 v2 etc I understand that to extract columns 1 and 2 I have to do awk F

How to remove symbols from a column using awk chr1 134901 139379 ENSG00000237683 5 chr1 860260 879955 ENSG00000187634 6 chr1 861264 866445 ENSG00000268179 1 chr1 879584 894689 ENSG00000188976 6 chr1 895967 901095 ENSG00000187961 9

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Awk Extracting Only Printable Characters From A Column

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Using Awk To Extract A String Between Different Characters

https://unix.stackexchange.com/questions/561827
After quite a bit of searching and testing I ve come up with VBoxManage list vms awk Test Machine sub sub print 3 9d0953a7 ca2a 4667 8c5b 1a9f550b2956 It works but I have to use to sub commands to extract it

Awk Extract String From A Field Unix amp Linux Stack Exchange

https://unix.stackexchange.com/questions/468010
3 Answers Sorted by 8 standard awk is not very good at extracting data out of fields based on patterns Some options include

Bash How To Extract A Text From Column In Awk Stack Overflow

https://stackoverflow.com/questions/42441557
5 Answers You could use grep to match the lines and only print the match grep o rs digit file rs16941 rs16942 rs1060915 rs1799966 rs206075 Prints only the matching part of the lines awk match 0 rs digit arr print arr 0 file rs16941 rs16942 rs1060915 rs1799966 rs206075

How To Print A Specific Column Of Characters Using Awk

https://stackoverflow.com/questions/31812312
c characters LIST select only these characters Or also sed sed r s 54 6 1 file 0 26 0 20 Or awk with substr awk print substr 0 55 6 file 0 26 0 20

How To Print Certain Column With Numbers Only In Awk

https://stackoverflow.com/questions/14329185
I have a text file that contains a mix of different number of columns per line I want to only print the lines if columns 3 4 and 5 of that line only contains number The trick is occasionally columns 3 4 and 5 will have a special character or embedded in them and I want to print these numbers too

Column1 column2 column3 column4 column5 column6 column7 column8 and I want awk to only print columns 2 till 7 I would use awk F print 2 3 4 5 6 7 file csv and get column2 column3 column4 column5 column6 column7 Awk NR FNR nums 1 next FNR in nums numberfile datafile only prints unique numbers in the numberfile What if the numberfile contains repeated entries Then sed is a better but much slower alternative sed nf

usr bin awk f BEGIN FS FNR 1 for col 1 col interesting col next print col Or if you prefer one liners awk F v txt interesting FNR 1 for c 1 c txt c next print c file1 file2